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A bullet is fired from gun. The force on...

A bullet is fired from gun. The force on bullet is, `F = 600 -2 xx 10^(5)` t newton. The force reduces to zero just when bullet leaves barrel. Find the impulse imparted to bullet

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`F = 600 -2 xx 10^(5)`t F becomes zero as soon as the bullet leaves the barrel, `0=600 - 2 xx 10^(5), t, 600 = 2 xx 10^(5)`t
`t = 3 xx 10^(-3) s` Impulse `=int_(0)^(t)Fdt`
`=int_(0)^(t)(600-2 xx 10^(5)t)dt = [600t -2 xx 10^(5) t^(2)/2]^(3 xx 10^(-3))`
`=0.9 Ns`
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