The apparent weight of a man in a lift is `w_1` when lift moves upwards with some acceleration and is `w_2` when it is accelerating down with same acceleration. Find the true weight of the man and acceleration of lift.

Explanation

(a) `w_(1) = w(1+a/g), w_(2) =w(1-a/g)`
`w_(1) + w_(2) = 2w rArr w=(w_(1)+w_(2))/2`
(b) `w_(1)/w_(2) =(w(1+a/g))/(w(1-a/g)), (g+a)/(g-a) =w_(1)/w_(2)`
`g/a=(w_(1) + w_(2))/(w_(1) -w_(2)) , a=g(w_(1) + w_(2))/((w_(1)+w_(2))`