When a car of 3mass 1000 kg is moving with a velocity of `20ms^(-1)` on a rough horizontal road, its engine is switched off. How far does the car move before it comes to rest if the coefficient of kinetic friction between the road and tyres of the car is 0.75 ?

Explanation

Here, `v= 20 ms^(-1), mu_(K) = 0.75, g = 10 ms^(-2)`
Stopping distance `S = v^(2)/(2mu_(K)g) = 26.67 m`