A stone of mass 2.0 kg is tied to the end of a string of 2m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone.

Explanation

m = 2.0 kg, r = 2 m, tension = 400N.
When the tension in the string reaches the breaking tension, the velocity of the body becomes maximum. Let the maximum velocity be v.
Tension = centripetal force
`40 = (mv^(2))/r rArr 400 =(2 xx v^(2))/2`
`v^(2) = 400, v= 20 ms^(-1)`