Home
Class 12
PHYSICS
The ends of a stretched wire of length '...

The ends of a stretched wire of length 'L' are fixed at x = 0 and x = L. In one experiment, the displacement of the wire is `y_(1) = A "sin"(pi x)/(L) sin wt` and the energy is `E_(1)` and in another experiment its displacement is `y_(2)=A "sin" (2pi x)/(L) sin 2 wt` and the energy `E_(2)` then

A

`E_2 = E_1 `

B

`E_2 = 2E_1 `

C

`E_2 = 4E_1 `

D

`E_2 = 16E_1`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III (LEVEL-II(ADVANCED) STRAIGHT OBJECTIVE TYPE QUESTIONS))|5 Videos

  • WAVE MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III (LEVEL-II(ADVANCED) MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS))|3 Videos

  • WAVE MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-II (LEVEL-II(ADVANCED) INTEGER TYPE QUESTIONS))|3 Videos

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise EXERCISE -3|66 Videos

  • WAVE MOTION AND SOUND

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|81 Videos

Similar Questions

Explore conceptually related problems

int e^(x//2) sin ((pi)/(4)+ (pi)/(2) ) dx =

If x + y = 2 pi // 3 and sin x / sin y = 2 , then the

A body is executing simple harmonic motion. At a displacement x its potential energy is E_1 and at a displacement y its potential energy is E_2 . The potential energy (E) at a discplcement (x+y) is,

int_(0)^(2pi) e^(x//2) sin (x/2 + pi/4) dx=