Home
Class 12
PHYSICS
Source and observer both start moving si...

Source and observer both start moving simultaneously from origin one along X-axis an the other along y-axis with speed of source = 2 (speed of observer). The graph between the apparent frequency observed by observer (t) and time (t) would be: (Here, f0 = natural frequency of source)

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-VI (LEVEL-II(ADVANCED) MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS))|2 Videos

  • WAVE MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-VI (LEVEL-II(ADVANCED) LINKED COMPREHENSION TYPE QUESTIONS))|6 Videos

  • WAVE MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-VI (LEVEL-I(MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS))|11 Videos

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise EXERCISE -3|66 Videos

  • WAVE MOTION AND SOUND

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|81 Videos

Similar Questions

Explore conceptually related problems

An observer is moving away from a sound source of frequency 100 Hz. If the obsever is moving with a velocity 49ms^-1 and the speed of sound in air is 330ms^-1 . The observed frequency is

Write down an expression for the observer frequency when both source and observer are moving relative to each other in the same direction.

(A) : When a source moves towards a stationary observer, the speed of source relative to the observer remains unchanged. (R): The apparent change in frequency is due to change in the wavelength brought by the motion of the source.

In Dopplers effect, when a source moves towards a stationary observer, the apparent increase in frequency is due to

An observer and a source emitting sound of frequency 120 Hz are the X-axis . The observer is stationary while the source of sound is in motion given by the equation x=3 sin omega (x is in metres and t is in seconds). If the diffrence between the maximum and minimum frequencies of the sound observed by the observers is 22Hz , then the value of omega is (speed of sound in air = 330 ms^(-1)