A body is projected vertically upwards with a speed of ` sqrt((GM)/R)` ( M is mass and R is radius of earth ) . The body will attain a height of

A body is projected up with a velocity equal to sqrt((9GM)/(8R)) , where M is the mass of the earth and R is the radius of the earth. The maximum distance it reaches from the centre of the earth is

A body is projected up with a velocity equal to sqrt((9GM)/(8R)) , where M is the mass of the earth and R is the radius of the earth. The maximum distance it reaches from the centre of the earth is

A body is projected vertically upwards with speed sqrt(g R_(e )) from the surface of earth. What is the maximum height attained by the body ? [ R_(e ) is the radius of earth, g is acceleration due to gravity]

A body of mass 2kg is projected vertically upwards with a speed of 3m//s . The maximum gravitational potential energy of the body is :

If a body is to be projected vertically upwards from earth's surface to reach a height of 10R where R is the radius of earth. The velocity required to be si is

A particle is projected vertically upward with with velocity sqrt((2)/(3)(GM)/(R )) from the surface of Earth. The height attained by it is (G, M, R have usual meanings)

A particle is projected vertically upward with with velocity sqrt((2)/(3)(GM)/(R )) from the surface of Earth. The height attained by it is (G, M, R have usual meanings)

A body is to be projected vertically upwards from earth's surface to reach a height of 9R , where R is the radius of earth. What is the velocity required to do so? Given g=10ms^(-2) and radius of earth =6.4xx10^(6)m .