The horizontal distance between two poles is 15m. The angle of depression of the top of the first pole as seen from the top of the second pole is `30o` . If the height of the second pole is 24 m, find the height of the first pole. `(sqrt(3)=1. 732)`

The horizontal distance between two poles is 15m. The angle of depression of the top of first pole as seen from the top of second pole is 30. If the height of the second pole is 24m, find the height of the first pole.Use v3=1.732)

The horizontal distance between two poles is 15 m. The angle of depression of the top of first pole as seen from the top of second pole is 30°. If the height of the second pole is 24 m, find the height of the first pole. Use v3 =1.732)

The horizontal distance between two towers si 60m and the angle of depression of the top of the first tower as seen from the top to the second is 30. If the height of the second tower is 150m , then the height of the first tower is

The horizontal distance between two building is 70m. The angle of depression of the top of the first building when seen from the top of the second building is 45^(@) . If the height of the second building is 120 m, find the height of the first building.

A pole stands erect on the ground. If the angle of elevation of the top of the pole from a point 90m away from the foot of the pole is 30^(@) , find the height of the pole.

From the top of a 50m high tower,the angles of depression of the top and bottom of a pole are observed to be 45o and 60o respectively. Find the height of the pole.

A pole 5 m high is fixed on the top of a tower. The angle of elevation of the top of the pole observed from a point 'A' on the ground is 60^(@) and the angle of depression to the point 'A' from the top of the tower is 45^(@) . Find the height of the tower. (sqrt(3)=1.732)