Let `veca` and `vecb` are non-collinear vectors and
`vecp=(x+4y)veca+(2x+y+1) vecb,`
`vecq=(-2x+y+2)veca+(2x-3y-1)vecb`
if `3vecp=2vecq`, then the values of x and y are -

IF veca and vecb are no collinear vectors and vecA=(x+4y)veca+(2x+y+1)vecb and vecB=(y-2x+2)vec+(2x-3y-1)vecb, find x and y such that 3vecA=2vecB .

If veca and vecb are two non collinear vectors and vecu = veca-(veca.vecb).vecb and vecv=veca x vecb then vecv is

If veca and vecb are non-collinear and vecp=xveca+(y+1)vecb,vecq=yveca+xvecb then what is the value of x and y if vecp=2vecq?

vecb and vecc are non- collinear if veca xx (vecb xx vecc) + (veca .vecb) vecb = ( 4-2x- sin y) vecb + ( x^(2) -1) vecc andd (vec. vecc) veca =veca then

vecb and vecc are non- collinear if veca xx (vecb xx vecc) + (veca .vecb) vecb = ( 4-2x- sin y) vecb + ( x^(2) -1) vecc andd (vec. vecc) veca =veca then

If vecp = veca - vecb , vecq = vec a + vec b and |veca| = |vecb| = 2 , then the value of |vecp xx vecq| is equal to

vecb and vecc are non- collinear if veca xx (vecb xx vecc) + (veca .vecb) vecb = ( 4-2x- sin y) vecb + ( x^(2) -1) vecc nad (veca. vecc) veca =veca then a. x =1 b. x = -1 c. y = (4 n+1) pi/2, n in I d. y ( 2n + 1) pi/2, n in I

If veca and vecb are two non collinear unit vectors and |veca+vecb|=sqrt(3) then find the value of (veca-vecb).(2veca+vecb)

If veca and vecb are two non collinear unit vectors and |veca+vecb|= sqrt3 , then find the value of (veca- vecb)*(2veca+ vecb)

Let vecb and vecc be non-collinear vectors. If veca is a vector such that veca.(vecb + vecc)=4 and veca xx (vecb xx vecc)=(x^(2) - 2x + 6)vecb + sin y.vecc , then (x,y) lies on the line: