The P.E. of a particle executing SHM at a distance x from its equilibrium position is

The ratio of kinetic energy and potential energy of a particle executing SHM at a distance of 2 cm from its equilibrium position is 3 : 2. What is the amplitude of vibration of the particle?

The acceleration of a particle executing SHM at a distance of 3 cm from equilibrium position is 5 cm//s^(2) . Its acceleration at a distance of 2 cm from equilibrium position is

When a particle executing SHM is at a distance of 0.03 m from the equilibrium position, its acceleration is 0.296m*s^(-2) . What is the time period of oscillation of the particle?

When a particle executing SHM is at a distance of 0.02 m from its mean position, then its kinetic energy is thrice its potential energy. Calculate the amplitude of motion of the particle.

When a particle executing SHM is at a distance of 0.02 m from its position of equilibrium, then its kinetic energy is twice its potential energy. Calculate the distance from the position of equilibrium where its potential energy is twice its kinetic energy.

The amplitude of a particle executing SHM is 0.1 m. The acceleration of the particle at a distance of 0.03 m from the equilibrium position is 0.12m*s^(-2) . What will be its velocity at a distance of 0.08 m from the position of equilibrium?

The potential energy of a particle executing simple harmonic motion at a distance X from the equilibrium position is proportional to …..

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.

A particle executes SHM with an amplitude of 13 cm and its velocity at a distance of 5 cm from the equilibrium position is 36cm*s^(-1) . Determine the maximum value of the restoring force. (Mass of the particle = 2g).