[" Consider the reaction: "],[qquad [P_(4)(s)+F_(2)(g)longrightarrow PF_(3)(g)" What mass of "F_(2)" is needed to produce "176g" of "PF_(3)" if the reaction has "80%" yield."]]

The % yield of ammonia as a function of time in the reaction, N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)'DeltaHlt0 at (p,T_(1)) is given below If this reaction is conducted at (p,T_(2)) , with T_(2)gtT_(1) the % yield by of ammonia as a function of time is represented by

The % yield of ammonia as a function of time in the reaction, N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)'DeltaHlt0 at (p,T_(1)) is given below If this reaction is conducted at (p,T_(1)) , with T_(2)gtT_(1) the % yield by of ammonia as a function of time is represented by

10 g of S reacts with excess of O_2 to form 15 g of SO_2. The % yield of the reaction is

In the reaction 2NH_(3)(g)+5F_(2) to N_(2)F_(4)+6HF 3.56g N_(2)F_(4) is obatained by mixing 2g NH_(3) and 8g F_(2) . The percentage yield of the production is: