Two sides of a triangle are given by the roots of the equation `x^2-5x+6=0` and the angle between the sides is `pi//2`. Then the perimeter of the triangle is

Two sides of a triangle are given by the roots of the equation x^(2)-5x+6=0 and the angle between the sides is (pi)/(3). Then the perimeter of the triangle is

Two sides of a triangle are given by the roots of the equation x^(2) - 5x+6 =0 and the angle between the sides is (pi)/(3). Then the perimeter of the triangle is-

Two sides of a triangle are given by the roots of the equation x^(2)-5x+6=0 and the angle between the sides is 60 ° Then the perimeter of the triangle is a

Two sides of a triangle are given by the roots of the equation x^(2)-2sqrt3x+2=0 . The angle between the sides is pi//3 . The perimeter of the triangle is

Two sides of a triangle are given by the roots of the equation x^(2) -2sqrt3 x+2 =0. The angle between the sides is (pi)/(3). Find the perimeter of Delta.

Two sides of a triangle are given by the roots of the equation x^(2) -2sqrt3 x+2 =0. The angle between the sides is (pi)/(3). Find the perimeter of Delta.

Two sides of a tariangle are given by the roots of the equation x^(2) -2sqrt3 x+2 =0. The angle between the sides is (pi)/(3). Find the perimeter of Delta.