The solubility product of `BaCl_(2)` is `3.2xx10^(-9)`. What will be solubility in mol `L^(-1)`

The solubility product of BaCl_2 is 4.0 xx 10 ^(–8) what will be its molar solubility in mol dm ^-3

Solubility product of BaCO_3 is 2.6 xx 10^(-9) . Estimate its solubility.

Solubility product of BaCl_(2) is 4xx10^(-9) . Its solubility in moles//litre would be

Solubility product of BaCl_(2) is 4xx10^(-9) . Its solubility in moles//litre would be

If the solubility product of Ni(OH)_2 is 4.0 xx 10^(-15) the solubility (in mol L^(-1) ) is

At 25^(@)C , the solubility product of a salt of MX_2 type is 3.2xx10^(-8) in water. The solubility (in mol/L) of MX_2 in water at the same temperature will be

The solubility product of Ag_2CrO_4 is 1.9xx10^(-12) at 300 K. What is its solubility ?

The solubility product of AgBr is 4.9xx10^(-9) . The solubility of AgBr will be