A wire of resistance `4 Omega` is bent through `180^@` at its mid point and the two halves are twisted together. Then the resistance is

A piece of wire of resistance 4Omega is bent through 180^(@) at its midpoint and the two halves are twisted together. Then the resistance is

A piece of wire of resistance 4Omega is bent through 180^(@) at its midpoint and the two halves are twisted together.Then the resistance is

A piece of wire of resistance 4 ohm is bent through 180 at its mid point and the two halves are twisted together. Then the resistance is

A piece of wire of resistance 4 ohm s is bent through 180^(@) at its mid point and the two halves are twisted together, then the resistance is

A piece of wire of resistance 4 ohm s is bent through 180^(@) at its mid point and the two halves are twisted together, then the resistance is

A 8 Omega resistance wire is bent through 180^(@) at its mid point and the two halves are twisted together. Then the resistance is

A wire of resistance 4 Omega is bent to form a circle. The resistance point A and B will be

A 4 Omega non insulated resistance wire is bent in the middle by 180^@ and both the halves are twisted with each other. What will be its new resistance ?

A wire of resistance 5 Omega is bent in the form of a closed circle. Find the resistance across the diameter of the circle.