In the adjoining figure, `DE || BC`. Prove that area `(Delta ACD) = " area " (Delta ABE)`

In the adjoining figure, DE || BC . Prove that area (DeltaACD) = " area " (DeltaABE)

In the given figure, BC||XY, BX||CA and AB ||YC . Prove that area (DeltaABX) = " area " (Delta ACY)

In the given figure, BC||XY, BX||CA and AB ||YC . Prove that area (DeltaABX) = area (Delta ACY)

In the adjoining figure, BD = DC and AE = ED. Prove that area of Delta ACE = (1)/(4) " area of " Delta ABC

In the adjoining figure, AD is the median of Delta ABC and X be any point on side AD. Prove that: area (Delta ABX) = " area " (Delta ACX)

In the adjoining figure, AD is the median of Delta ABC and X be any point on side AD. Prove that: area (Delta ABX) = " area " (Delta ACX)

In the given figure, DE // BC. Prove that Delta ADE and Delta ABC are similar

In Delta ABC ,D is a point in side AB and E is a point in AC. If DE is parallel to BC, and BE and CD intersect each other at point 0, prove that: " area "(Delta ACD) =" area "(Delta ABE)

In the parallelogram ABCD , the side AB is produced to the point X.so that BX= AB. The line DX cuts BC at E. Prove that : Area ( Delta AED) = 2 xx " area " (Delta CEX).

In Delta ABC ,D is a point in side AB and E is a point in AC. If DE is parallel to BC, and BE and CD intersect each other at point 0, prove that: " area " (Delta OBD) = " area " (Delta OCE)