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Two sides of a rhombus ABCD are parallel...

Two sides of a rhombus ABCD are parallel to the lines y = x + 2 and y = 7x + 3 If the diagonals of the rhombus intersect at the point (1, 2) and the vertex A is on the y-axis, then vertex A can be

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y=x+2 slope=1
y=7x+3 slope=7
O(1,2)=`((0+m)/2,(n+alpha)/2)=((x+a)/2,(b+y)/2)`
m=2 x+a=2
`n+alpha=4 b+y=4`
`m_(ab)=(b-alpha)/(a-0)=1=b-alpha=a`
`m_(bc)=(b-n)/(a-2)=7=b-n=7(a-2)`
AB=BC
...
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