In the Boolean algebra : `overline(A).overline(B) = ….`

In the Boolean algebra : overline(A+B) is not equal to :

The input of A and B for the Boolean expression (overline(A+B)).(overline(A.B))=1 is.

What will be the values of input A and B for the Boolean expression (overline A + B) . (overline A . B) = 1 ?

If overline(A),overline(B), overline(C) are three non-coplanar vector, the (overline(A)*overline(B)timesoverline(C))/(overline(C)*overline(A)timesoverline(B))+(overline(B)*overline(A)timesoverline(C))/(overline(C)*overline(A)timesoverline(B))=

If A = 1 , B= 0 then in terms of Boolean algebra , A + overline (B) equals

If overline(a),overline(b), overline(c) are three non-coplanar vectors and overline(p), overline(q), overline(r) are vectors defined by the relations overline(p)=(overline(b)timesoverline(c))/([[overline(a), overline(b), overline(c)]]), overline(q)=(overline(c)timesoverline(a))/([[overline(a), overline(b), overline(c)]]), overline(r)=(overline(a)timesoverline(b))/([[overline(a), overline(b), overline(c)]]) , then (overline(a)+overline(b))*overline(p)+(overline(b)+overline(c))*overline(q)+(overline(c)+overline(a))*overline(r)=