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OSWAAL PUBLICATION-INVERSE TRIGONOMETRIC FUNCTIONS-SHORT ANSWER TYPE QUESTIONS - II
- Prove that t a n^(-1)((cosx)/(1+sinx))=pi/4-x/2,\ x in (-pi/2,pi/2)
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- cos(sin^-1 (3/5)+ cot^-1(3/2)) = 6/(5sqrt13)
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- cos^(-1)((4)/(5))+cos^(-1)((12)/(13))=
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- Solve for x : 2tan^(-1)(sinx)=tan^(-1)(2secx),\ x!=pi/2
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- Prove that: "sin"[cot^(-1){"cos"(tan^(-1)x)}]=sqrt((x^21)/(x^2+2)) ...
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- Prove that : 2tan^(-1)((3)/(4))-tan^(-1)((17)/(31))=(pi)/(4).
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- Solve for x : tan^(-1)((2x)/(1-x^2))+cot^(-1)((1-x^2)/(2x))=pi/3,-1ltx...
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- tan^(- 1)(1/4)+tan^(- 1)(2/9)=1/2tan^(- 1)(4/3)
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- solve: cos(2sin^-1x)=1/9
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- Find the value of tan^(-1)(x/y)-tan^(-1)((x-y)/(x+y))
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- (9pi)/(8)-(9)/(4)sin^(-1)""(1)/(3)=(9)/(4)sin^(-1)""(2sqrt(2))/(3) (...
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- Solve sin^(-1)(1-x)-2s in^(-1)x=pi/2
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- prove that tan^-1(1)+tan^-1(2) +tan^-1(3) = pi
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- Solve for x : tan^(-1)(x+2)+tan^(-1)(x-2)=tan^(-1)(8/(79)) , x >0
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- Solve for x:tan^(-1)((x)/(2))+tan^(-1)((x)/(3))=(pi)/(4), sqrt6gtx gt0...
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- prove that 2tan^-1 1/3+tan^-1 1/7=pi/4
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- cos^(-1)x+sin^(-1)(x/2)= pi/6
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- Prove the following: tan^(-1)sqrt(x)=1/2cos^(-1)((1-x)/(1+x)),\ x\ \ ...
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- Prove the following: tan^(-1)x+tan^(-1)((2x)/(1-x^2))=tan^(-1)((3x-x^3...
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- Prove the following: "cos"[tan^(-1){sin(cos t^(-1)x)}]= sqrt((1+x^2)/...
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