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Evaluate : int"cosec"x("cosec "x-cotx)dx...

Evaluate : `int"cosec"x("cosec "x-cotx)dx.`

Text Solution

Verified by Experts

The correct Answer is:
`-cotx+"cosec "x+c`
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Find int cosecx(cosecx + cotx)dx .

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Knowledge Check

  • int cosec(x-a)cosecx dx =

    A
    `1/sina log[sin(x-a). Cosec x]`
    B
    `1/sina log [sin(x-a).sinx]`
    C
    `(-1)/sin a log[sin x cosec(x-a)]`
    D
    `(-1)/sin a log[sin(x-a)sinx]`
  • sec (cosec^(-1) x)=

    A
    `cosec(sec ^(-1) x)`
    B
    `cot x`
    C
    `pi`
    D
    none of these
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