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int "sec x" ("sec" x + tan x) dx....

`int "sec x" ("sec" x + tan x) dx`.

Text Solution

Verified by Experts

The correct Answer is:
`tanx+secx+c`
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int "sec" ("sec" x + tan x) dx .

Evaluate int secx ( sec x + tan x ) dx

Knowledge Check

  • int dx/(a sec x + b tanx) =

    A
    log (a sec x + b tan x)
    B
    1/b log (a + b sin x)
    C
    1/a log (a + b sin x)
    D
    b log (a + b sin x)
  • int (sec x dx)/(log (sec x +tan x)) =

    A
    sec x + tan x
    B
    log (sec x)
    C
    log [log (sec x + tan x)]
    D
    log (sec x + tan x)
  • int e^(x) (1+tan x + tan^(2) x) dx

    A
    `e^(x) cos x + c`
    B
    `e^(x) tan x + c`
    C
    `e^(x) sec x + c`
    D
    `e^(x) sin x + c`
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    int e^(x) sec x (1 + tan x) dx .

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    The integral int (sec^(2) x)/((sec x+tan x)^(9//2))dx equals : (for some arbitrary constant k)

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