Home
Class 10
MATHS
DeltaABC~DeltaDEF. If area (DeltaABC)=2....

`DeltaABC~DeltaDEF`. If area `(DeltaABC)=2.89m^(2)`, area `(DeltaDEF)=2.25m^(2)`, and AB = 1.5 m, find DE.

Text Solution

Verified by Experts

The correct Answer is:
1.3 cm
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    ZEN PUBLICATION|Exercise ZEE ADDITIONAL QUESTIONS - SHORT ANSWER TYPE - 1 QUESTIONS|15 Videos
  • TRIANGLES

    ZEN PUBLICATION|Exercise ZEE ADDITIONAL QUESTIONS - SHORT ANSWER TYPE - 2 QUESTIONS|7 Videos
  • TRIANGLES

    ZEN PUBLICATION|Exercise ZEE ADDITIONAL QUESTIONS -MULTIPLE-CHOICE QUESTIONS|11 Videos
  • SURFACE AREAS AND VOLUMES

    ZEN PUBLICATION|Exercise ZEE ADDITIONAL QUESTIONS -HOTS [HIGHER ORDER THINKING SKILLS]-QUESTIONS|11 Videos

Similar Questions

Explore conceptually related problems

If DeltaABC~DeltaDEF, BC=3cm, EF=4cm , and Area of DeltaABC=54cm^(2) , then Area of Delta DEF is

Let DeltaABC~DeltaDEF and their areas be , respectively , 64 cm^(2) and 121cm^(2) . If EF = 15.4 cm, find BC

Given DeltaABC~DeltaPQR . If (AB)/(PQ)=1/3 , find ("Area "DeltaABC)/("Area "DeltaPQR) .

DeltaABC~DeltaDEF . If AB = 4 cm, AC = 3.5 cm, BC = 3 cm, and EF = 6 cm, the perimeter of DeltaDEF is

If Delta=a^(2)-(b-c)^(2) , where Delta is area of DeltaABC , then tanA is

In the given fig DeltaDGH~DeltaDEF, DH=8cm, DF=12cm, DG=(3x-1) cm and DE=(4x+2) cm, Find the lengths of DG and DE. OR D is a point on the side BC of DeltaABC such that lfloorADC=lfloorBAC . Prove that (CA)/(CD)=(CB)/(CA) .

In a DeltaABC , if A=18^(@) , b-a=2 , ab=4 , then the triangle is

In a DeltaABC , tan.(A)/(2) and tan.(B)/(2) satisfy 6x^(2)-5x+1=0 . Then :

In DeltaABC and DeltaDEF , AB= DE, AB abs DE, BC= EF and BC abs EF . Vertices A, B and C are joined to vertices D, E and F respectively. Show that DeltaABC~=DeltaDEF .