Prove that the area of a segment of a circle with radius r and sector angle`theta` is `r^2/2[(pi theta)/180^@-sin theta]`

Length of an arc of a sector of a circle of radius r and angle theta is

Area of a sector of angle p (in degrees) of a circle with radius R is

lim_(theta rarr pi/2) (pi/2- theta)/(cot theta) =

Figure shows a sector of a circle with centre O and angle 'theta' . Prove that: (a) Perimeter of shaded region is r(tan theta+sec theta+ (pi theta)/(180^@)-1) units (b) area of the shaded region is r^2/2 (tan theta-(pi theta)/(180^@))sq. units

Write the formula to find area of a sector of a circle, if angle at the centre is 'theta' degrees.

If A and B are two points of a circle of radius r with centre at the point O and angleAOB = theta (in radians) then the area of the sector AOB is

Prove that y = (4 sin theta)/((2 + cos theta)) - theta is an increasing on theta in [0, (pi)/2] .

If 3 sin 2 theta=2 sin 3 theta and 0 lt theta lt pi then sin theta=

Prove that: (1-sin theta + cos theta)^(2) = 2(1+ cos theta) (1-sin theta) .

Find the area of the circle whose parametric equations x=3+2 cos theta and y=1+2 sin theta.