The area of a triangle is 5 square units. Two of its vertices are (2,1) and (3,-2) and the third vertex lies on y = x + 3, find the third vertex.

The centroid of the triangle is (2,7) and two of its vertices are (4,8) and (-2,6) and third vertex is

The base vertices of an isosceles triangle are (7,9) and (3,-7), then the third vertex is

Find the area of a triangle whose vertices are (1,3), (2,5) and (7,5) using determinants

The area of triangle whose vertices are (1,2,3), (2,5,-1) and (-1,1,2) is

The equation of one side of a rectangle is 3 x-4 y-10=0 and the coordinates of two of its vertices are (-2,1) and (2,4) . Then the area of the rectangle is

The two opposite vertices of a square are (-1,2) and (3, 2). Find the coordinates of the other two vertices.

Find the area of the triangle whose vertices are : (2, 3), (-1, 0), (2, -4)

If a vertex of a triangle is (1, 1) and the mid-points of two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is :

Find the area of the triangle with vertices A(1,1,2), B(2,3,5) and C(1,5,5).