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The value of phase at t=0 is phi and is ...

The value of phase at `t=0` is `phi` and is called ......

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The maximum values of the phasors (currents and voltage) in AC circuits can be treated as vectors rotating with an angular frequency equal to the angular frequency of the rotor of the generator. If the phase difference between two phasors vec(A_(1)) and vec(A_(2)) is phi the resultant phasor is : A = sqrt(A_(1)^(2) + A_(2)^(2) + 2A_(1)A_(2) cos phi) and the phase of vec(A) with respects to A_(1) is beta = "tan"^(-1) (A_(2) sin phi)/(A_(1) + A_(2) cos phi) RHS value The rms value of y = f (t) is y_("rms") = {(int_(0)^(T) [f(t)]^(2) dt)/(T)}^((1)/(2)) Average value The average value of y = f (t) is y_(av) = (int_(0)^(T) ydt)/(T) Using the above concept, answer the following questions. The average value of i in i - t graph (Semi circular) is

The maximum values of the phasors (currents and voltage) in AC circuits can be treated as vectors rotating with an angular frequency equal to the angular frequency of the rotor of the generator. If the phase difference between two phasors vec(A_(1)) and vec(A_(2)) is phi the resultant phasor is : A = sqrt(A_(1)^(2) + A_(2)^(2) + 2A_(1)A_(2) cos phi) and the phase of vec(A) with respects to A_(1) is beta = "tan"^(-1) (A_(2) sin phi)/(A_(1) + A_(2) cos phi) RHS value The rms value of y = f (t) is y_("rms") = {(int_(0)^(T) [f(t)]^(2) dt)/(T)}^((1)/(2)) Average value The average value of y = f (t) is y_(av) = (int_(0)^(T) ydt)/(T) Using the above concept, answer the following questions. The rms value of i_(3) is

Determine the average value of the electromotive force E_(m) over one period, ie, over the time from t= 0 to t=T, if electromotive force is computed by the formula E = E_(0) " sin "(2pi t)/(T) where T is the duration of the period in seconds, E_(0) the amplitude (the maximum value) of the electromotive force corresponding to the value t= 0.25T. The fraction (2pi t)/(T) is called the phase.

A wave is travelling along x-axis . The disturbance at x=0 and t=0 is A/2 and is increasing , where A is amplitude of the wave. If Y= sin (kx-omegat+phi) , then the initial phase is alpha pi . Find alpha

For the plane wave y=2.5xx10^(-0.02x)cos(800t-0.82x+pi/2) , write down (i) the general expression for phase phi (ii) the phase at x=0, t=0 (iii) the phase different between the point separated by 20 cm along x-axis. (iv) the change in phase at a given place 0.6 milli second and (v) the amplitude at x=100m. Take units of y,t,x as 10^(-5)cm , s and m respectively.