Let b=6 ,with a and c satisfying the equation `(a+b+c)^(2)+(a+8b+7c)^(2)=0`. If `alpha` and `beta` are the roots of the quadratic equation `ax^(2)+bx+c=0`, then `sum_(n=0)^(oo)((1)/(alpha)+(1)/(beta))^(n)`

If alpha,beta are the roots of the quadratic equation ax^(2)+bx+c=0 then alpha beta =

If alpha,beta are the roots of the quadratic equation x^(2)+bx-c=0, the equation whose roots are b and c, is

Let a,b, and c be three real numbers satistying [a,b,c][(1,9,7),(8,2,7),(7,3,7)]=[0,0,0] Let b=6, with a and c satisfying (E). If alpha and beta are the roots of the quadratic equation ax^2+bx+c=0 then sum_(n=0)^oo (1/alpha+1/beta)^n is (A) 6 (B) 7 (C) 6/7 (D) oo

If alpha& beta are the roots of the equation ax^(2)+bx+c=0, then (1+alpha+alpha^(2))(1+beta+beta^(2))=

If alpha and beta ( alpha

If alpha,beta are the roots of the equation ax^(2)+bx+c=0, then prove that (alpha)/(beta)+(beta)/(alpha)=(b^(2)-2ac)/(ac)