Let `d_(1)` and `d_(2)` be the lengths of perpendiculars drawn from foci `S'` and `S` of the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` to the tangent at any point `P` to the ellipse. Then `S'P : SP` is equal to

Let d_1a n dd_2 be the length of the perpendiculars drawn from the foci Sa n dS ' of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 to the tangent at any point P on the ellipse. Then, S P : S^(prime)P= d_1: d_2 (b) d_2: d_1 d1 2:d2 2 (d) sqrt(d_1):sqrt(d_2)

If M_(1) and M_(2) are the feet of perpendiculars from foci F_(1) and F_(2) of the ellipse (x^(2))/(64)+(y^(2))/(25)=1 on the tangent at any point P of the ellipse then

If p is the length of the perpendicular from the focus S of the ellipse x^(2)/a^(2)+y^(2)/b^(2) = 1 to a tangent at a point P on the ellipse, then (2a)/(SP)-1=

If 'd' be the length of perpendicular drawn from origin to any normal of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 then 'd' cannot exceed

The product of the perpendiculars from the two foci of the ellipse (x^(2))/(9)+(y^(2))/(25)=1 on the tangent at any point on the ellipse

If F_(1) and F_(2) are the feet of the perpendiculars from foci s_(1) and s_(2) of an ellipse 3x^(2)+5y^(2)=15 on the tangent at any point P on the ellipse then (s_(1)F_(1))(S_(2)F_(2)) =

If F_(1) and F_(2) are the feet of the perpendiculars from the foci S_(1)andS_(2) of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 on the tangent at any point P on the ellipse,then prove that S_(1)F_(1)+S_(2)F_(2)>=8

If F_(1) and F_(2) are the feet of the perpendiculars from foci S_(1) and S_(2) of the ellipse (x^(2 /(25 +y^(2 /(16 =1 on the tangent at any point P of the ellipse,then the minimum value of S_(1 F_(1 +S_(2 F_(2 is 1) 2, 2) 3, 3) 6, 4) 8