A car and a truck,are moving with same K .E. or same momentum or same velocity and applying same retarding force.Their stopping distances are `S_(1)` and `S_(2)` respectively:

A lorry and a car moving with the same KE are brought to rest by applying the same retarding force. Then

Two cars of same mass are moving with velocities v_(1) and v_(2) respectively. If they are stopped by supplying same breaking power in time t_(1) and t_(2) respectively then (v_(1))/(v_(2)) is

A truck and a car are moving with equal velocity. On applying the brakes both will stop after certain distance, then

Two bodies of masses 1 kg and 2 kg moving withy same velocities are stopped by the same force. Then, the ratio of their stopping distances is

Four similar cars having exactly the same mass are running at the same speed on the same road when breakes are applied at the same time. The cars come to stop covering distance of 5 m, 5.5 m, 4.8 m and 5.2 m respectively. The friction between the brake pads and discs will be the maximum in the car which travels the distance of :

A truck and a car are moving with the same K.E. on a straight road. Their engines are simultaneously switched off. Which one will stop at a lesser distance ?