A bus turns a slippery road having coefficient of friction of `0*5` with a speed of 110 m/s .The minimum radius of the arc in which bus turns is [ Take g = 10 `m/s^(2)] `

A bus turns a slippery road having coefficient of friction of 0*5 with a speed of 10 m/s .The minimum radius of the arc in which bus turns is [ Take g = 10 m/s^(2)]

A car takes a turn on a slippery road at a safe speed of 9.8 m/s .If the coefficient of friction is 0.2 the manimum radius of the are in which the car takes a trun is

A car turns a corner on a slippery road at a constant speed of 10 m /s . If the coefficient of friction is 0.5, the minimum radius of the arc in meter in which the car turns is

A car turns a corner on a slippery road at a constant speed of s m /10 . If the coefficient of friction is 0.5, the minimum radius of the arc in meter in which the car turns is

A car turns a corner on a slippery road at a canstant speed of 12m//s . If the co0efficient is 0.4 , the minimum radius of the arc in metres in which the car truns is.

A vac moving with a speed of 108 km //h on level road where coefficient of friction between tyres and rod is 0.5 .For the safe driving of van the minimum radius of curvature of the rod will be (g=10 m//s^(2))

A car turns a corner on a slippery road at a speed of 12ms^(-1) . If the coefficient of friction is 0.4, the (in m) in which the car turns is

A car is moving on a horizontal circular tracck of radius 0*2 km with a constant speed. If coefficient of friction between tyres of car and road is 0*45 , then speed of a car may be [ Take g = 10 m/s^(2)]

A person is driving a vehicle at uniform speed of 5 m s^(-1) on a level curved track of radius 5m. The coefficient of static friction between tyres and road is 0.1. Will the person slip while taking the turn with the same speed ? Take g=10 ms^(-2) . Choose the correct statement.

A van is moving with a speed of 108 km / hr on level road where the coefficient of fraction between the tyres and the road is 0.5 for the safe driving of the van , the minimum radius of curvature of the road will be ( g=10 m//s^(2) )