Let `P (3, 6), Q(3costheta,3sintheta),R(3sintheta,-3costheta)` then the locus of centroid of `PQR` is

(3costheta+cos3theta)/(3sintheta-sin3theta)=

Let A={:[(costheta,-sintheta),(-sintheta,-costheta)]:} then inverse of A is

The vertices of a DeltaABC has coordinates (costheta,sintheta),(sintheta,-costheta) and (1,2). As theta varies the locus of centroid of the triangle is the circle

sqrt(3)costheta+sintheta=2

If (sintheta+costheta)/(sintheta-costheta)=3 then the value of sin^(4)theta is :

Let A=[{:(costheta,sintheta),(-sintheta,costheta):}] , then |2A| is equal to

Let A=[{:(costheta,sintheta),(-sintheta,costheta):}] , then |2A| is equal to

sintheta - sqrt(3)costheta =1

If 3sintheta+4costheta=5 ,then 4sintheta-3costheta=