If `a^2+9b^2-4c^2=6ab`, then the family of lines `ax + by + c= 0` are concurrent at:

If a^2-b^2-c^2-2ab=0 , then the family of lines ax+by+c=0 are concurrent at the points

If 6a^2-3b^2-c^2+7ab-ac+4bc-0 , then the family of lines ax+by+c=0 is concurrent at

If 6a^2-3b^2-c^2+7ab-ac+4bc=0 , then the family of lines ax+by+c=0 is concurrent at

If 16a^(2)+25b^(2)-c^(2)=40ab, then the family of lines ax+by+c=0 is concurrent at the point(s)

If 4a^2+9b^2-c^2+12ab= 0 then the family of straight lines ax + by +c=0 is concurrent at : (A) (-3,2) or (2,3) (B) (-2,3) or (2,-3) (C) (3,2) or (-3,-2) (D) (2,3) or (-2,-3)

If 4a^2+9b^2_c^2+12ab=0 then the family of straight lines ax+by+c=0 is concurrent at

If a^2+b^2-c^2-2ab = 0 , then the family of straight lines ax + by + c = 0 is concurrent at the points

2a+b+2c=0(a,b,c in R), then the family of lines ax+by+c=0 is concurrent at

Statement I: The points (a,0),(0,b) and (1,1) will be collinear if 1/a+1/b=1 Statement II: If 4a^(2)+9b^(2)-c^(2)+12ab=0 , then the family of lines ax+by+c=0 is either concurrent at (2,3) or at (-2,-3). Then which of the followng is true

If a^2+b^2-c^2-2ab = 0 , then the family of straight lines ax + by + c = 0