`|x^2-4x+3|+|x^2-6x+8|=|2x-5|`

Solve for x (i) |x+1|=4x+3 (ii) |x+1|=|x+3| (iii) 7|x-2|-|x-7|=5 (iv) ||x-1|-2|=6x+8 (v) |2x^(2)-3x+1|=|x^(2)+x-3|

If Delta(x)=|(x^2+4x-3, 2x+4, 13), (2x^2+5x-9, 4x+5, 26), (8x^2-6x+1, 16x-6, 104)|=a x^3+b x^2+c x+d , then

If f(x)=|[3x^2-x+3,6x-1,4],[6x^2-4x+5,12x-4,8],[3x^2+2x+5,6x+2,4]|, then the degree of the polynomial f(x) is

Add: 2x^(3) - 9x^(2) + 8, 3x^(2) - 6x - 5, 7x^(3) - 10x + 1 and 3 + 2x - 5x^(2) - 4x^(3)

Add 7x^(2) -8x + 5, 3x^(2) -8x +5 and -6x^(2) + 15x - 5

Find the intervals in which the following function are increasing or decreasing. f(x)=10-6x-2x^2 f(x)=x^2+2x-5 f(x)=6-9x-x^2 f(x)=2x^3-12 x^2+18 x+15 f(x)=5+36 x+3x^2-2x^3 f(x)=8+36 x+3x^2-2x^3 f(x)=5x^3-15 x^2-120 x+3 f(x)=x^3-6x^2-36 x+2 f(x)=2x^3-15 x^2+36 x+1 f(x)=2x^3+9x^2+20 f(x)=2x^3-9x^2+12 x-5 f(x)=6+12 x+3x^2-2x^3 f(x)=2x^3-24 x+107 f(x)=-2x^3-9x^2-12 x+1 f(x)=(x-1)(x-2)^2 f(x)=x^3-12 x^2+36 x+17 f(x)=2x^3-24+7 f(x)=3/(10)x^4-4/5x^3-3x^2+(36)/5x+11 f(x)=x^4-4x f(x)=(x^4)/4+2/3x^3-5/2x^2-6x+7 f(x)=x^4-4x^3+4x^2+15 f(x)=5x^(3/2)-3x^(5/2),x >0 f(x)==x^8+6x^2 f(x)==x^3-6x^2+9x+15 f(x)={x(x-2)}^2 f(x)=3x^4-4x^3-12 x^2+5 f(x)=3/2x^4-4x^3-45 x^2+51 f(x)=log(2+x)-(2x)/(2+x),xR

2x+3y=8 4x-5y=-6

Find the square root of (6x^(2) + 5x - 6) (6x^(2) - x - 2) (4x^(2) + 8x + 3)