A wheel has a moment of inertia of `5xx10^(-3) kg m"^(2)` and is making `"20 rev/s".` What is the magnitude of the torque required to stop it in 10 s?

A wheel has moment of inertia 5 xx 10^(-3) kg m^(2) and is making 20 "rev" s^(-1) . The torque needed to stop it in 10 s is….. xx 10^(-2) N-m

A wheel has moment of inertia 5 xx 10^(-3) kg m^(2) and is making 20 "rev" s^(-1) . The torque needed to stop it in 10 s is….. xx 10^(-2) N-m

A fly wheel of moment of inertia 4xx10^(-3)kgm^(2) is makign 10 revolution per second. The torque required to stop it in 5 second is:

A wheel of moment of inertia 2 xx 10^3 kg m^2 is rotating at uniform angular speed of 4 rad/s,.then . the torque required to stop it in one second is,

A wheel of moment of inertia 2.0 xx 10^3 kgm^2 is rotating at uniform angular speed of 4 rads^-1 . What is the torque required to stop it in one second.

A fly wheel has a moment of inertia ok 5 kgm^2 . If 10^5 joule of work is done on it, what is its angular speed? Find torqure required to stop it in 10 seonds