Let X be the number of successes in 'n' independent Bernoulli trials with probability of success `p=(3)/(4)`, the least value of 'n' so that `P(x ge 1) ge 0.9375` is

What is the most probable number of successes in 10 trials with probability of success (2)/(3)?(d)4(b)7(a)10(c)5

Consider 5 independent Bernoulli's trials each with probability of success p. If the probability of at least one failure is greater than or equal to (31)/(32) , then p lies in the interval :

Consider 5 independent Bernoulli's trials each with probability of at least one failure is greater than or equal to 31/32, then p lies in the interval

Consider 5 independent Bernoulli.s trials each with probability of success p. If the probability of at least one failure is greater than or equal to (31)/(32) , then p lies in the interval : (1) (1/2,3/4] (2) (3/4,(11)/(12)] (3) [0,1/2] (4) ((11)/(12),1]

Consider 5 independent Bernoulli.s trials each with probability of success p.If the probability of at least one failure is greater than or equal to (31)/(32), then p lies in the interval : (1)((1)/(2),(3)/(4)] (2) ((3)/(4),(11)/(12)] (3) [0,(1)/(2)] (4) ((11)/(12),1]

Consider 5 independent Bernoulli.s trials each with probability of success p. If the probability of at least one failure is greater than or equal to (31)/(32) , then p lies in the interval : (1) (1/2,3/4] (2) (3/4,(11)/(12)] (3) [0,1/2] (4) ((11)/(12),1]