Home
Class 11
PHYSICS
The escape velocity from the surface of ...

The escape velocity from the surface of the earth is (where `R_(E)` is the radius of the earth )

Promotional Banner

Similar Questions

Explore conceptually related problems

A body is projected up with a velocity up with a velocity equal to 3/4 of the escape velocity from the surface of the earth . The height it reaches is ( Radius of the earth = R )

A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :

A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :

Statement-1: Escape velocity is independent of the angle of projection. Statement-2: Escape velocity from the surface of earth is sqrt(2gR) where R is radius of earth.

Statement-1: Escape velocity is independent of the angle of projection. Statement-2: Escape velocity from the surface of earth is sqrt(2gR) where R is radius of earth.

Statement-1: Escape velocity is independent of the angle of projection. Statement-2: Escape velocity from the surface of earth is sqrt(2gR) where R is radius of earth.

The escape velocity from the surface of the earth of radius R and density rho

The escape velocity from the surface of the earth of radius R and density rho

The escape velocity from the surface of the earth is V_(e) . The escape velcotiy from the surface of a planet whose mass and radius are three times those of the earth, will be