If the radius of earth is 6400km, calcu late (a) angu lar velocity (b) linear velocity and (c) radial accelration for a point on its equator considering its spin motion alone. What will be the values of above quantities if the pint is at the pole?

If the radius of the rarth is 6400 km, then the linear velocity of a point on the equator will be nearly

If the radius of the rarth is 6400 km, then the linear velocity of a point on the equator will be nearly

The earth, radius 6400 km, makes one revolution about its own axis in 24 hours. The centripetal acceleration of a point on its equator is nearly

Calculate the centripetal acceleation of a point on the equator of earth due to the rotatin of earth about its wn axis . Radius of earth = 6400 km .

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth =6400km )

Consider a spherical planet which is rotating about its axis such that the speed of a point on its equator is 'v' and the effective acceleration due to gravity on the equator is 1/3 of its value at the poles. What is the escape velocity for the particle at the pole of this planet?