The time period 'T' of a simple pendulum of length 'l' is given by T = `2pisqrt(l/g)`.Find the percentage error in the value of 'T' if the percentage error in the value of 'l' is 2%.

The time T of of oscillation of a simple pendulum of length l is given by T=2pisqrt(l/g) . Find the percentage error in T, corresponding to an error of 2% in the value of l.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.

The time T of oscillation of as simple pendulum of length l is given by T=2pi sqrt(l/g) . The percentage error in T corresponding to an error of 2% in the value of l is

The time T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

Time period T of a simple pendulum of length l is given by T=2pisqrt(l/g) . If the length is increased by 2% , then an approximate change in the time period is

Time period T of a simple pendulum of length l is given by T = 2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is

Time period T of a simple pendulum of length l is given by T=2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is

The time t of a complete oscillation of a simple pendulum of length l is given by t2pisqrt(l/g) where g is gravitational constant. Find the approximate percentage of error in t when the percentage of error in l is 1%.