The equation of the line through the origin and perpendiculr to the line joining `(a,0)and (-a,0)` is

Find the equation of the straight line throught the origin and perpendicular to the line joining (4,0) and (0,4) . Hence . Show that the point (4,0) is the image of the point (0,4) with respect to the line.

The equation of a line through origin and perpendicular to the line 23x-11y+7=0 is :

The equation of the lines through the origin and perpendicular to the lines ax^(2) + 2hxy + bh^(2) = 0 is

The equation of the line passing through origin and perpendicular to the line 7x – 3y + 4 = 0

Combined equation of the lines passing through the origin and perpendicular to the lines 2x^(2)-3xy+y^(2)=0 is

The combined equation of the pair of lines through the origin and perpendicular to the pair of lines given by ax^(2)+2hxy+by^(2)=0 , is

The combined equation of the pair of lines through the origin and perpendicular to the pair of lines given by ax^(2)+2hxy+by^(2)=0 , is

The combined equation of the pair of lines through the origin and perpendicular to the pair of lines given by ax^(2)+2hxy+by^(2)=0 , is