A particle oscillates as per the equation `x = (7 cos 0.5 pi t)m`, the time taken by the particle to move from the mean position to a point `3.5m` away is

A particle oscillates, according to the equation x = 5 cos (pit//2) m. Then the particle moves from equilibrium position to the position of maximum displacement in time of

A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x=5cos(0.5pit) where t is in seconds. The particle moves from the position of equilibrium to the position of maximum displacement in time………………

A particle oscillate according to y= 7 sin 0.5 pi t . Time taken by particle from equilibrium position to maximum displacement is……….

A particle is oscillating according to the equation X=7 cos 0.5 pit , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle is osicllating according to the equation X= 7 cos (0.5 pi t) , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x = 10cos2pit , where 't' is in seconds. The particle moves from the position of maximum displacement to equilibrium in time.

How much time will a particle oscillating according to equation y = 10 sin (0.9 pit )m take to move from mean position to position of maximum displacement ?