The distance of point `(1,-2,-3)` from plane `x-y+z=5` measured parallel to the line `x/2=y/3=z/(-6)` is

The distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line x/2=y/3=z/-6 , is

Find the distance of the point (1,-2,3) from the plane x-y+z=5, measured parallel to the line x/2=y/3=z/(-6)

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line x/2=y/3=z/-6 .

The distance of the point (1,-2,3) from the plane x-y+z = 5, measured parallel to the line x/2 = y/3 = z/(-6) is .............

The distance of the point (1,-2,3) from the plane x-y+z-5=0 , measured parallel to the line x/2=y/3=(z-1)/-6 is equal to

The distance of the point (1,-2,3) from the plane x-y+z-5=0 , measured parallel to the line x/2=y/3=(z-1)/-6 is equal to

The distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line (x)/(2)=(y)/(3)=(z)/(-6), is

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line (x)/(2)=(y)/(3)=(z)/(-6) .

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line (x-1)/2=(y-3)/3=(z+2)/-6 .

Find the distance of the point (1,0,-3) from plane x-y-z=9 measured parallel to the line (x-2)/2=(y+2)/2=(z-6)/(-6)