The equation of the latus rectum of a parabola is `x+y=8` and the equation of the tangent at the vertex is `x+y=12.` Then find the length of the latus rectum.

If the equation of latus rectum of a parabola is x+y-8=0 and the equation of the tangent at the vertex is x+y-12=0, then the length of the latus rectum is-

Consider the parabola y^2=12x Find the length of the latus rectum.

Find the length of the latus rectum of the parabola x^(2) = -8y .

Find the length of the latus rectum of the parabola x^(2) = -8y .

Let A be the vertex and L the length of the latus rectum of the parabola,y^(2)-2y-4x-7=0 The equation of the parabola with A as vertex 2L the length of the latus rectum and the axis at right angles to that of the given curve is:

Find the length of the latus rectum of the parabola x^2=-8y

y^2+2y-x+5=0 represents a parabola. Find its vertex, equation of axis, equation of latus rectum, coordinates of the focus, equation of the directrix, extremities of the latus rectum, and the length of the latus rectum.

y^2+2y-x+5=0 represents a parabola. Find its vertex, equation of axis, equation of latus rectum, coordinates of the focus, equation of the directrix, extremities of the latus rectum, and the length of the latus rectum.