The time period of a simple pendulum of length L as measured in an elevator descending with acceleration g / 3 is

The time period of a simple pendulum inside a stationary lift is T. If it starts descending with acceleration g/5. the new period of the simple pendulum will be

The time period of a simple pendulum inside a stationary lift is T. If it starts descending with acceleration g/5. the new period of the simple pendulum will be

The time period of a simple pendulum in a lift descending with constant acceleration g is

An expression for the time period of oscillation of a simple pendulum of length 'L' at a place where acceleration due to gravity is g is T prop ((L)/(g))^((1)/(x)) , then the vaslue of x is

Find the expression of time period of a simple pendulum of length l.

The time period T of a simple pendulum depends on length L and acceleration due to gravity g Establish a relation using dimensions.

Time period of simple pendulum of length l at a place, where acceleration due to gravity is g and period T. Then period of simple pendulum of the same length at a place where the acceleration due to gravity 1.02 g will be

The period of a simple pendulum inside a stationary lift is T. The lift accelerates upwards with an acceleration of g/3 . The time period of pendulum will be