The de-Broglie wavelength of an electron is same as the wavelength of an photon.The K.E.of photon is 'x' times the K.E.of the electron then 'x' is (M- mass of electron h - Planck's constant C - Velocity of light)

The de-Broglie wavelength of an electron is same as the wavelength of a photon. The energy of a photon is ‘x’ times the K.E. of the electron, then ‘x’ is: (m-mass of electron, h-Planck’s constant, c - velocity of light)

The de-Broglie wavelength of an electron is same as the wavelength of a photon. The energy of a photon is ‘x’ times the K.E. of the electron, then ‘x’ is: (m-mass of electron, h-Planck’s constant, c - velocity of light)

The de Broglie wavelength of an electron and the wavelength of a photon are same. The ratio between the energy of the photon and the momentum of the electron is

The de-Broglie wavelength of a photon is the same as the wavelength of electron, show that kinetic energy of photon is (2mclambda)/h times the kinetic energy of electron, where m is the mass of electron and c is the velocity of light.

The de-broglie wavelength of a photon is twice the de-broglie wavelength of an electron. The speed of the electron is v_(e)=c/100 . Then

The de-broglie wavelength of a photon is twice the de-broglie wavelength of an electron. The speed of the electron is v_(e)=c/100 . Then

The de-broglie wavelength of a photon is twice the de-broglie wavelength of an electron. The speed of the electron is v_(e)=c/100 . Then

What will be the de - Broglie wavelength of an electron having K.E of 500 eV?