Home
Class 11
CHEMISTRY
For an element (X) the successive ionisa...

For an element `(X)` the successive ionisation energies, `IE_(1), IE_(2), IE_(3), IE_(4)` and `IE_(5)` are `800, 2427, 3658, 25024` and `32824 kJ mol^(-1)` respectively, then that what is the number of valence electrons present in the element?

Promotional Banner

Similar Questions

Explore conceptually related problems

The five successive energies of an element are 800, 2427, 3658, 25024 and 32824 kJ mol^(-1) respectively. The number of valence electron is

The five successive energies of an element are 800, 2427, 3658, 25024 and 32824 kJ mol^(-1) respectively. The number of valence electron is

The five successive ionisation energies energies of an element 'X' are 800, 1427, 2658, 25024 and 32824 "KJ mole"^(-1) respectively . The valency of 'X' is :

The five successive ionisation energies energies of an element 'X' are 800, 1427, 2658, 25024 and 32824 "KJ mole"^(-1) respectively . The valency of 'X' is :

Five successive ionisation enthalpies of an element are 800, 2427, 3638, 25024 & 32824kJ*mol^(-1) respectively. The number of valence electrons of the element is-

The values of IE_(1),IE_(2),IE_(3),IE_(4) and IE_(5) of an element are 7.1, 14.3, 34.5, 46.8 and 162.2 eV respectively. The element is likely to be

The successive ionization energies for element X is given below IE_(1) : 250 kJ "mo"^(-1) IE_(2) : 820 kJ "mo"^(-1) IE_(3) : 1100 kJ "mo"^(-1) IE_(4) : 1400 kJ "mo"^(-1) Find out the number of valence electrons for the elements X.