A cyclist starts from rest and moves with a constant acceleration of 1 `m//s^(2)`. A boy who is 48 m behind the cyclist starts moving with a constant velocity of `10 m//s`. After how much time the boy meets the cyclist?

A bus starts from rest with an acceleration of 1 m//s^(2) A man who is 48 m behind the bus starts with a uniform velocity of 10 m s^(-1) . Then after how much time the man will catch the bus ?

A bus starts from rest and moves with constant acceleration 8 m//s^(2) . At the same time, a car traveling with a constant velocity 16 m//s overtakes and passes the bus. After how much time and at what distance the bus overtakes the car?

A boy is moving with constant velocity 12 m//s . When he is 32 m behind a cyclist, the cyclist starts from rest and moves under constant acceleration 2 m//s^(2) . After how much time the boy meets the cyclist? Explain reason for two answers.

(a) A body starting from rest moves with a constant acceleration of 5 m//s^(2) . What is velocity of the body after 10 sec ? (b) A scooter moving with a velocity of 18 km//h is brought to rest in 5 s by applying brakes. What is the acceleration produced ?

A bus starts moving with acceleration 2 ms^-2 . A cyclist 96 m behind the bus starts simultaneously towards the bus at a constant speed of 20 m//s . After what time will he be able to overtake the bus ?

A bus starts moving with acceleration 2 ms^-2 . A cyclist 96 m behind the bus starts simultaneously towards the bus at a constant speed of 20 m//s . After what time will he be able to overtake the bus ?

A bus starts moving with acceleration 2 ms^-2 . A cyclist 96 m behind the bus starts simultaneously towards the bus at a constant speed of 20 m//s . After what time will he be able to overtake the bus ?