A hoop rolls on a horizontal ground without slipping with linear speed `v`. Speed of a particle `P` on the circumference of the hoop at angle `theta` is :

A disc rolls over a horizontal floor without slipping with a linear speed of 5 cm/sec. Then the linear speed of a particle on its rim, with respect to the floor, when it is in its highest position is?

A disc rolls over a horizontal floor without slipping with a linear speed of 5 cm/sec. Then the linear speed of a particle on its rim, with respect to the floor, when it is in its highest position is?

A disc rolls on ground without slipping . Velocity of centre of mass is v. There is a point P on circumference of disc at angle theta . Suppose v_(p) is the speed of this point. Then, match the following the following table.

A disc rolls on ground without slipping. Velocity of centre of mass is v . There is a point P on circumference of disc at angle theta . Suppose, v_(P) is the speed of this point. Then, match the following columns {:(,"Column-I",,"Column-II"),("(A)","If" theta=60^(@),"(p)",v_(P)=sqrt(2)v),("(B)","If" theta=90^(@),"(q)",v_(P)=v),("(C)","If" theta=120^(@),"(r)",v_(P)=2v),("D)","If" theta=180^(@),"(s)",v_(P)=sqrt(3)v):}

A smooth hoop lie as on a smooth horizontal table and is fixed. A particle is projected on the table form a point A on the inner circumference of the hoop at angle theta with radius vector . If e be the coefficient of restitution and the particle returns to the point of projection after two successive impacts. The final angle theta' made by velocity vector with radius of hoop is

A ring of radius R rolls on a horizontal ground with linear speed v and angular speed omega . For what value of theta the velocity of point P is in vertical direction (vltRomega) .