Find the distance between the directrices of the ellipse `(x^2)/(36)+(y^2)/(20)=1.`

Find the distance between the directrices of th ellipse (x^(2))/(36) + (y^(2))/(20) = 1 .

Find the distance between the directrices the ellipse (x^2)/(36)+(y^2)/(20)=1.

The distance between the directrices of the ellipse (x^(2))/(36)+(y^(2))/(20)=1 is

Filnd the distance between the directrices the ellipse (x^2)/(36)+(y^2)/(20)=1.

The distance between the directrices of the ellipse x^2/4+y^2/9=1 is:

The distance between the directrices of ellipse (x^(2))/(36)+(y^(2))/(20)=1 is (i) 81 (ii) 9 (iii) 18 (iv) None of these

If the distance between the foci and the distance between the directrices of the hyperbola (x^2)/(a^2) - (y^2)/(b^2) = 1 are in the ratio 3:2,then a:b is

If the distance between the foci and the distance between the directrices of the hyperbola (x^(2))/(a^(2)) -(y^(2))/(b^(2)) =1 are in the ratio 3 : 2 then a : b is

If the distance between the foci and the distance between the directrices of the hyperbola x^(2)/(a_2 )-y^(2)/b_2 =1 are in the ratio 3:2