The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. Its total energy will be

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

When the amplitude of a particle executing S.H.M. is increased slightly its period

When the displacement of a particle executing SHM is one-fourth of its amplitude, what fraction of the total energy is the kinetic energy?

When the displacement of a particle executing SHM is one-fourth of its amplitude, what fraction of the total energy is the kinetic energy?

If the mass of a particle executing SHM is m and its angular frequency is omega , then time period of its oscillation will be

A particle is executing SHM with time period T. If time period of its total mechanical energy isT' then (T')/(T) is

A particle is executing SHM with time period T. If time period of its total mechanical energy isT' then (T')/(T) is

A particle executing SHM has a total energy E. Another particle of twice the mass of the first particle executes SHM with 4 times the frequency and twice the amplitude of the first. Its total energy is