When a light of wavelength 4000 Å falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 6000 Å is suficient for photo emission. The work functions of the two emitters are in the ratio of

When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitted , light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

When light of wavelength 300nm (nanometer) falls on a photoelectric emitter, photoelectrons are liberated. For another emitter,however light of 600nm wavelength is sufficient for creating photoemission. The ratio of the work functions of the two emitters is 2 : x, then the value of x is

When light of wavelength 300 nm or less falls on aphotoelectric emitter A, photoelectrons are emitted. For another emitter B, light of wavelength 600 nm is sufficient for releasing photoelectorns. The ratio of the work function of emitter A to B is

When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectrons are emitted. In another emitter however light of 600 nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters ?

When light of wavelength 3000 Å falls on a photosensitive surface (A) photoelectrons are emitted. However, for another photoemitter (B), light of wavelength 6000 Å is required for the emission of photoelectrons. What is the ratio of the work functions of A and B ?

When light of wavelength 300 nm (nanometre) falls on a photoelectric emitter , however light of 600 nm wavelength is sufficient for creating photoemission . What is the ratio of the work functions of the two emitters ?

When light of wavelength 3600 nm falls on a photosensitive plate, photoelectrons are emitted. However, for another photoelectric emitter, light of 6000 nm is sufficient to produce photoemission. What is the ratio of the work functions of the two emitters ?