Time period T of a simple pendulum of length l is given by `T=2pisqrt((l)/(g))`. If the length is increased by `2%` then an approximate change in the time period is

The time period 'T' of a simple pendulum of length 'l' is given by T = 2pisqrt(l/g) .Find the percentage error in the value of 'T' if the percentage error in the value of 'l' is 2%.

The time period 'T' of a simple pendulum of length 'l' is given by T = 2pisqrt(l/g) .Find the percentage error in the value of 'T' if the percentage error in the value of 'l' is 2%.

If length of simple pendulum is increased by 6% then percentage change in the time-period will be

If length of simple pendulum is increased by 6% then percentage change in the time-period will be

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.

The time t of a complete oscillation of a simple pendulum of length l is given by t2pisqrt(l/g) where g is gravitational constant. Find the approximate percentage of error in t when the percentage of error in l is 1%.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

The time T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.