The displacement of a particle performing S.H.M. is x = 3 sin (314 t) + 4 cos (314 t). Then the initial phase angle is,

The displacement of a particle performing S.H.M. is, x = 3 sin (314t) + 4 cos (314t), where x and t are in CGS units. Then the amplitude of the S.H.M. is,

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then the speed of the particle at 0.1 s will be

The displacement equation of a particle performing S.H.M. is x = 10 sin (2pit+(pi)/(6)) m. Then the initial displacement of a particle is

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then acceleration of the particle at 0.1 s is

The displacement xi in centimetres of a particle is xi = 3 sin 314 t + 4 cos 314 t . Amplitude and initial phase are

The displacement xi in centimetres of a particle is xi = 3 sin 314 t + 4 cos 314 t . Amplitude and initial phase are

The displacement of a particle in S.H.M is in opposite phase with

The displacement of a particle performing S.H.M is x=A" "sin(omegat+prop) . The quantity prop is called